From c8ea2705a7115208f59839828a82b42a58293576 Mon Sep 17 00:00:00 2001
From: Brad King <brad.king@kitware.com>
Date: Tue, 29 Jun 2010 10:01:59 -0400
Subject: [PATCH] Use same type in both cases of '?:' operator

Both possible result values need to be convertible to the same type.
Some compilers fail to recognize that they can construct std::string
from the empty string literal, so state it explicitly.
---
 Source/cmCoreTryCompile.cxx | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Source/cmCoreTryCompile.cxx b/Source/cmCoreTryCompile.cxx
index fcec3e902..b8a0c95b1 100644
--- a/Source/cmCoreTryCompile.cxx
+++ b/Source/cmCoreTryCompile.cxx
@@ -178,7 +178,7 @@ int cmCoreTryCompile::TryCompileCode(std::vector<std::string> const& argv)
 
     const char* rulesOverrideBase = "CMAKE_USER_MAKE_RULES_OVERRIDE";
     std::string rulesOverrideLang =
-      rulesOverrideBase + (lang ? std::string("_") + lang : "");
+      rulesOverrideBase + (lang ? std::string("_") + lang : std::string(""));
     if(const char* rulesOverridePath =
        this->Makefile->GetDefinition(rulesOverrideLang.c_str()))
       {